x^2-6x+10=-6+2x

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Solution for x^2-6x+10=-6+2x equation: 



x^2-6x+10=-6+2x

We move all terms to the left:

x^2-6x+10-(-6+2x)=0

We add all the numbers together, and all the variables

x^2-6x-(2x-6)+10=0

We get rid of parentheses

x^2-6x-2x+6+10=0

We add all the numbers together, and all the variables

x^2-8x+16=0

a = 1; b = -8; c = +16;
Δ = b2-4ac
Δ = -82-4·1·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{8}{2}=4$

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